• Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function? PLeaseee?

    Best answer: h(t) = -16t^2 + v₀t + h₀ Where: h = the height of the object at any given point in time (in ft) t = time the object is in motion (in sec) h₀ = the initial height (in ft) v₀ = the initial velocity (in ft/sec) If v₀ < 0, the object was propelled downward v₀ = 0, the ball was dropped from rest with no... show more
    Best answer: h(t) = -16t^2 + v₀t + h₀

    Where:

    h = the height of the object at any given point in time (in ft)
    t = time the object is in motion (in sec)
    h₀ = the initial height (in ft)
    v₀ = the initial velocity (in ft/sec)
    If v₀ < 0, the object was propelled downward
    v₀ = 0, the ball was dropped from rest with no initial velocity
    v₀ > 0, the ball was propelled upward

    So in this case we have:

    h(t) = -16t^2 + 37t + 6

    v₀ = 37 ft/sec
    h₀ = 6 ft

    The first derivative of position, h(t) in this case is the velocity:

    v(t) = dh/dt = -32t + 37

    v(3.2) = -32 * 3.2 + 37 = - 65.4 ft/sec => the negative sign is the direction of velocity which is downward

    The above makes D) => the correct choice

    however he ball will hit the ground when the height is zero we can find the time that takes place:

    -16t^2 + 37t + 6 = 0
    using the quadratic formula the approximated times are:
    t ≈ - 0.15 , 2.5 sec => disregarding the negative time, thus the ball hits the ground at t = 2.5 sec, which means at t = 3.2 sec, the ball should be resting on the ground so there is either an error or we are missing some more information
    6 answers · 1 day ago
  • What is 1 third of 2.5 litres of paint?

    19 answers · 3 days ago
  • How many yards = .3 miles?

    14 answers · 2 days ago
  • (4-x)/(x-5) > 1/(1-x)?

    Best answer: (4 - x)/(x - 5) > 1/(1 - x) (4 - x)(1 - x) > x - 5 4 - 5x + x^2 > x - 5 x^2 - 6x + 9 > 0 (x - 3)^2 > 0 ---> x =/= 3. Not done yet; x = 1 (excluded value) x = 4 (a zero on the left side), and x = 5 (excluded value) must be used for interval bounds. If x < 1, you have plus/minus > 1/plus... show more
    Best answer: (4 - x)/(x - 5) > 1/(1 - x)

    (4 - x)(1 - x) > x - 5

    4 - 5x + x^2 > x - 5

    x^2 - 6x + 9 > 0

    (x - 3)^2 > 0 ---> x =/= 3.

    Not done yet; x = 1 (excluded value) x = 4 (a zero on the left side), and x = 5 (excluded value) must be used for interval bounds.

    If x < 1, you have plus/minus > 1/plus ---> minus > plus. Doesn't work.

    If 1 < x < 3, you have plus/minus > 1/minus ---> minus > minus. Doable.

    If 3 < x < 4, the same happens as in the previous case (minus > minus). Doable.

    If 4 < x < 5, you have minus/minus > 1/minus ---> plus > minus. This works.

    If x > 5, you have minus/plus > 1/minus ---> minus > minus. But this fails because you have a number increasing toward -1 that is greater than a negative unit fraction -- a false statement because the negative unit fraction is closer to 0.

    Solution interval union should be (1, 3) U (3, 5); 1 < x < 3 or 3 < x < 5 should satisfy the inequality.
    7 answers · 3 days ago
  • What s 100×150cm in foot and inches?

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  • What is the solution to -16 + 2x= -64?

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  • How many ounces in a pound?

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  • Statistics question?

    What percent of the year is 154 days?
    What percent of the year is 154 days?
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  • What is the sum of --18 + 13?

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  • How to verbally say an index root?

    If 3 is the index of the square root of 27, how do you verbally say it?
    If 3 is the index of the square root of 27, how do you verbally say it?
    9 answers · 2 days ago
  • Math help!!?

    Solve algebraically Y=3+2x-x^2 Y=2x^2+5x-3
    Solve algebraically Y=3+2x-x^2 Y=2x^2+5x-3
    5 answers · 5 hours ago
  • Is 1998 late 90s?

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  • (1-cos x)(sin x - 1) = 0?

    Best answer: Zero Product Rule: If two factors are multiplied together to give zero, then one of the two must be zero. (there is no other way to get zero in a multiplication). It could be 1 - cos(x) = 0 then 1 = cos(x) x = 0, pi, 2pi, etc... x = k(pi) where k is any integer (positive or negative, including zero) Or, it could... show more
    Best answer: Zero Product Rule:
    If two factors are multiplied together to give zero, then one of the two must be zero.
    (there is no other way to get zero in a multiplication).

    It could be
    1 - cos(x) = 0
    then
    1 = cos(x)
    x = 0, pi, 2pi, etc...
    x = k(pi) where k is any integer (positive or negative, including zero)

    Or, it could be
    sin(x) - 1 = 0
    then
    sin(x) = 1
    x = pi/2, 3pi/2, 9pi/2, 11pi/2 (not 5pi/2 not 7pi/2), and so on...
    8 answers · 2 days ago
  • A 16-oz jar of peanut butter in the shape of a right circular cylinder is 5in high and 3in in diameter and sells for $1.60.?

    In the same store, a 26-oz jar of the same brand is 5&1/2in high and 3&1/4in in diameter. If the cost is directly proportional to volume, what should the price of the larger jar be? If the cost is directly proportional to weight, what should the price of the larger jar be?
    In the same store, a 26-oz jar of the same brand is 5&1/2in high and 3&1/4in in diameter. If the cost is directly proportional to volume, what should the price of the larger jar be? If the cost is directly proportional to weight, what should the price of the larger jar be?
    5 answers · 4 days ago
  • In a class of 50 students, 38 use desktop computers, 16 use laptops. What is the maximum number of students who use both?

    Best answer: In the extreme case, all 16 that use laptops could be completely inside the set of students who use desktop computers. In other words, the maximum who use both is 16. As for the minimum, we can't have the two sets being disjoint (no overlap) because 16 + 38 = 54. That means there has to be an overlap of at... show more
    Best answer: In the extreme case, all 16 that use laptops could be completely inside the set of students who use desktop computers. In other words, the maximum who use both is 16.

    As for the minimum, we can't have the two sets being disjoint (no overlap) because 16 + 38 = 54. That means there has to be an overlap of at least 4 students that use both a laptop and a desktop computer.

    Answer:
    Minimum of 4 students
    Maximum of 16 students

    Update:

    If it helps, imagine you have 16 labels that say "laptop" and 38 labels that say "desktop" and you have 50 students.

    You could give a "laptop" and a "desktop" label to the same 16 students. That's the maximum you could have --> 16 maximum.
    (The remaining 22 "desktop" labels would go to any of the remaining students)
    16 (both), 22 (just desktop), 12 (no computer)

    And for the other way, you could give all the "laptop" labels to 16 students which leaves 34 students. You could give them 34 of the "desktop" labels but you'd have to give 4 "desktop" labels to those students that already have a "laptop" label. That's the minimum you could have with both --> 4 minimum
    4 (both), 34 (just desktop), 12 (just laptop)
    8 answers · 5 days ago
  • What is 1/5+ 1/4?

    10 answers · 3 days ago